0.12(y-7)+0.10y=0.16y-0.6

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Solution for 0.12(y-7)+0.10y=0.16y-0.6 equation: 



0.12(y-7)+0.10y=0.16y-0.6

We move all terms to the left:

0.12(y-7)+0.10y-(0.16y-0.6)=0

We add all the numbers together, and all the variables

0.10y+0.12(y-7)-(0.16y-0.6)=0

We multiply parentheses

0.10y+0.12y-(0.16y-0.6)-0.84=0

We get rid of parentheses

0.10y+0.12y-0.16y+0.6-0.84=0

We add all the numbers together, and all the variables

0.06y-0.24=0

We move all terms containing y to the left, all other terms to the right

0.06y=0.24

y=0.24/0.06

y=4

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