0.12(y-6)+0.16y=0.2y-0.01(60)

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Solution for 0.12(y-6)+0.16y=0.2y-0.01(60) equation: 



0.12(y-6)+0.16y=0.2y-0.01(60)

We move all terms to the left:

0.12(y-6)+0.16y-(0.2y-0.01(60))=0

We add all the numbers together, and all the variables

0.12(y-6)+0.16y-(0.2y-0.016)=0

We add all the numbers together, and all the variables

0.16y+0.12(y-6)-(0.2y-0.016)=0

We multiply parentheses

0.16y+0.12y-(0.2y-0.016)-0.72=0

We get rid of parentheses

0.16y+0.12y-0.2y+0.016-0.72=0

We add all the numbers together, and all the variables

0.08y-0.704=0

We move all terms containing y to the left, all other terms to the right

0.08y=0.704

y=0.704/0.08

y=8+0.064/0.08

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