0.12(y-3)+0.12y=0.20y-0.6

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Solution for 0.12(y-3)+0.12y=0.20y-0.6 equation: 



0.12(y-3)+0.12y=0.20y-0.6

We move all terms to the left:

0.12(y-3)+0.12y-(0.20y-0.6)=0

We add all the numbers together, and all the variables

0.12y+0.12(y-3)-(0.20y-0.6)=0

We multiply parentheses

0.12y+0.12y-(0.20y-0.6)-0.36=0

We get rid of parentheses

0.12y+0.12y-0.20y+0.6-0.36=0

We add all the numbers together, and all the variables

0.04y+0.24=0

We move all terms containing y to the left, all other terms to the right

0.04y=-0.24

y=-0.24/0.04

y=-6

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