0.12(y-3)+0.02y=0.16y-0.01(20)

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Solution for 0.12(y-3)+0.02y=0.16y-0.01(20) equation: 



0.12(y-3)+0.02y=0.16y-0.01(20)

We move all terms to the left:

0.12(y-3)+0.02y-(0.16y-0.01(20))=0

We add all the numbers together, and all the variables

0.12(y-3)+0.02y-(0.16y-0.012)=0

We add all the numbers together, and all the variables

0.02y+0.12(y-3)-(0.16y-0.012)=0

We multiply parentheses

0.02y+0.12y-(0.16y-0.012)-0.36=0

We get rid of parentheses

0.02y+0.12y-0.16y+0.012-0.36=0

We add all the numbers together, and all the variables

-0.02y-0.348=0

We move all terms containing y to the left, all other terms to the right

-0.02y=0.348

y=0.348/-0.02

y=-17+0.008/0.02

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