0.12(x+1)=0.16(1-x)

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Solution for 0.12(x+1)=0.16(1-x) equation: 



0.12(x+1)=0.16(1-x)

We move all terms to the left:

0.12(x+1)-(0.16(1-x))=0

We add all the numbers together, and all the variables

0.12(x+1)-(0.16(-1x+1))=0

We multiply parentheses

0.12x-(0.16(-1x+1))+0.12=0



We calculate terms in parentheses: -(0.16(-1x+1)), so:

0.16(-1x+1)

We multiply parentheses

-0.16x+0.16

Back to the equation:

-(-0.16x+0.16)



We get rid of parentheses

0.12x+0.16x-0.16+0.12=0

We add all the numbers together, and all the variables

0.28x-0.04=0

We move all terms containing x to the left, all other terms to the right

0.28x=0.04

x=0.04/0.28

x=0.04/0.28

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