0.11x+0.6(x-4)=0.01(4x-2)

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Solution for 0.11x+0.6(x-4)=0.01(4x-2) equation: 



0.11x+0.6(x-4)=0.01(4x-2)

We move all terms to the left:

0.11x+0.6(x-4)-(0.01(4x-2))=0

We multiply parentheses

0.11x+0.6x-(0.01(4x-2))-2.4=0



We calculate terms in parentheses: -(0.01(4x-2)), so:

0.01(4x-2)

We multiply parentheses

0.04x-0.02

Back to the equation:

-(0.04x-0.02)



We add all the numbers together, and all the variables

0.71x-(0.04x-0.02)-2.4=0

We get rid of parentheses

0.71x-0.04x+0.02-2.4=0

We add all the numbers together, and all the variables

0.67x-2.38=0

We move all terms containing x to the left, all other terms to the right

0.67x=2.38

x=2.38/0.67

x=3+0.37/0.67

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