0.06y(y-7)+0.18y=0.16y-0.1

Solution for 0.06y(y-7)+0.18y=0.16y-0.1 equation:

0.06y(y-7)+0.18y=0.16y-0.1

We move all terms to the left:

0.06y(y-7)+0.18y-(0.16y-0.1)=0

We add all the numbers together, and all the variables

0.18y+0.06y(y-7)-(0.16y-0.1)=0

We multiply parentheses

0y^2+0.18y+0y-(0.16y-0.1)=0

We get rid of parentheses

0y^2+0.18y+0y-0.16y+0.1=0

We add all the numbers together, and all the variables

y^2+1.02y+0.1=0

a = 1; b = 1.02; c = +0.1;
Δ = b2-4ac
Δ = 1.022-4·1·0.1
Δ = 0.6404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.02)-\sqrt{0.6404}}{2*1}=\frac{-1.02-\sqrt{0.6404}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.02)+\sqrt{0.6404}}{2*1}=\frac{-1.02+\sqrt{0.6404}}{2}
$