0.05(2t-1)=0.10(t-4)+0.35

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Solution for 0.05(2t-1)=0.10(t-4)+0.35 equation: 



0.05(2t-1)=0.10(t-4)+0.35

We move all terms to the left:

0.05(2t-1)-(0.10(t-4)+0.35)=0

We multiply parentheses

0.1t-(0.10(t-4)+0.35)-0.05=0



We calculate terms in parentheses: -(0.10(t-4)+0.35), so:

0.10(t-4)+0.35

We multiply parentheses

0.1t-0.4+0.35

We add all the numbers together, and all the variables

0.1t-0.05

Back to the equation:

-(0.1t-0.05)



We get rid of parentheses

0.1t-0.1t+0.05-0.05=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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