0.04(2t+1)=0.08(t-3)+0.28

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Solution for 0.04(2t+1)=0.08(t-3)+0.28 equation: 


Simplifying
0.04(2t + 1) = 0.08(t + -3) + 0.28

Reorder the terms:
0.04(1 + 2t) = 0.08(t + -3) + 0.28
(1 * 0.04 + 2t * 0.04) = 0.08(t + -3) + 0.28
(0.04 + 0.08t) = 0.08(t + -3) + 0.28

Reorder the terms:
0.04 + 0.08t = 0.08(-3 + t) + 0.28
0.04 + 0.08t = (-3 * 0.08 + t * 0.08) + 0.28
0.04 + 0.08t = (-0.24 + 0.08t) + 0.28

Reorder the terms:
0.04 + 0.08t = -0.24 + 0.28 + 0.08t

Combine like terms: -0.24 + 0.28 = 0.04
0.04 + 0.08t = 0.04 + 0.08t

Add '-0.04' to each side of the equation.
0.04 + -0.04 + 0.08t = 0.04 + -0.04 + 0.08t

Combine like terms: 0.04 + -0.04 = 0.00
0.00 + 0.08t = 0.04 + -0.04 + 0.08t
0.08t = 0.04 + -0.04 + 0.08t

Combine like terms: 0.04 + -0.04 = 0.00
0.08t = 0.00 + 0.08t
0.08t = 0.08t

Add '-0.08t' to each side of the equation.
0.08t + -0.08t = 0.08t + -0.08t

Combine like terms: 0.08t + -0.08t = 0.00
0.00 = 0.08t + -0.08t

Combine like terms: 0.08t + -0.08t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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