0.03(2t-1)=0.06(t+4)-0.27

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Solution for 0.03(2t-1)=0.06(t+4)-0.27 equation: 



0.03(2t-1)=0.06(t+4)-0.27

We move all terms to the left:

0.03(2t-1)-(0.06(t+4)-0.27)=0

We multiply parentheses

0.06t-(0.06(t+4)-0.27)-0.03=0



We calculate terms in parentheses: -(0.06(t+4)-0.27), so:

0.06(t+4)-0.27

We multiply parentheses

0.06t+0.24-0.27

We add all the numbers together, and all the variables

0.06t-0.03

Back to the equation:

-(0.06t-0.03)



We get rid of parentheses

0.06t-0.06t+0.03-0.03=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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