0.02(y-4)+0.12y=0.20y-0.2

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Solution for 0.02(y-4)+0.12y=0.20y-0.2 equation:



0.02(y-4)+0.12y=0.20y-0.2
We move all terms to the left:
0.02(y-4)+0.12y-(0.20y-0.2)=0
We add all the numbers together, and all the variables
0.12y+0.02(y-4)-(0.20y-0.2)=0
We multiply parentheses
0.12y+0.02y-(0.20y-0.2)-0.08=0
We get rid of parentheses
0.12y+0.02y-0.20y+0.2-0.08=0
We add all the numbers together, and all the variables
-0.06y+0.12=0
We move all terms containing y to the left, all other terms to the right
-0.06y=-0.12
y=-0.12/-0.06
y=+2

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