0.02(x-3)=0.01(x-5)+1

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Solution for 0.02(x-3)=0.01(x-5)+1 equation: 



0.02(x-3)=0.01(x-5)+1

We move all terms to the left:

0.02(x-3)-(0.01(x-5)+1)=0

We multiply parentheses

0.02x-(0.01(x-5)+1)-0.06=0



We calculate terms in parentheses: -(0.01(x-5)+1), so:

0.01(x-5)+1

We multiply parentheses

0.01x-0.05+1

We add all the numbers together, and all the variables

0.01x+0.95

Back to the equation:

-(0.01x+0.95)



We get rid of parentheses

0.02x-0.01x-0.95-0.06=0

We add all the numbers together, and all the variables

0.01x-1.01=0

We move all terms containing x to the left, all other terms to the right

0.01x=1.01

x=1.01/0.01

x=101

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