0.02(2t-4)=0.04(t-1)-0.04

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Solution for 0.02(2t-4)=0.04(t-1)-0.04 equation:


Simplifying
0.02(2t + -4) = 0.04(t + -1) + -0.04

Reorder the terms:
0.02(-4 + 2t) = 0.04(t + -1) + -0.04
(-4 * 0.02 + 2t * 0.02) = 0.04(t + -1) + -0.04
(-0.08 + 0.04t) = 0.04(t + -1) + -0.04

Reorder the terms:
-0.08 + 0.04t = 0.04(-1 + t) + -0.04
-0.08 + 0.04t = (-1 * 0.04 + t * 0.04) + -0.04
-0.08 + 0.04t = (-0.04 + 0.04t) + -0.04

Reorder the terms:
-0.08 + 0.04t = -0.04 + -0.04 + 0.04t

Combine like terms: -0.04 + -0.04 = -0.08
-0.08 + 0.04t = -0.08 + 0.04t

Add '0.08' to each side of the equation.
-0.08 + 0.08 + 0.04t = -0.08 + 0.08 + 0.04t

Combine like terms: -0.08 + 0.08 = 0.00
0.00 + 0.04t = -0.08 + 0.08 + 0.04t
0.04t = -0.08 + 0.08 + 0.04t

Combine like terms: -0.08 + 0.08 = 0.00
0.04t = 0.00 + 0.04t
0.04t = 0.04t

Add '-0.04t' to each side of the equation.
0.04t + -0.04t = 0.04t + -0.04t

Combine like terms: 0.04t + -0.04t = 0.00
0.00 = 0.04t + -0.04t

Combine like terms: 0.04t + -0.04t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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