0.015=(0.041x)2x

Solution for 0.015=(0.041x)2x equation:

0.015=(0.041x)2x

We move all terms to the left:

0.015-((0.041x)2x)=0

We add all the numbers together, and all the variables

-((+0.041x)2x)+0.015=0


We calculate terms in parentheses: -((+0.041x)2x), so:

(+0.041x)2x

We multiply parentheses

0x^2

We add all the numbers together, and all the variables

x^2

Back to the equation:

-(x^2)


We add all the numbers together, and all the variables

-1x^2+0.015=0

a = -1; b = 0; c = +0.015;
Δ = b2-4ac
Δ = 02-4·(-1)·0.015
Δ = 0.06
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.06}}{2*-1}=\frac{0-\sqrt{0.06}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.06}}{2*-1}=\frac{0+\sqrt{0.06}}{-2}
=\frac{\sqrt{}}{-2}
$