0,6(x+2)-(0,4x-0,6=0,2(1-x)

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Solution for 0,6(x+2)-(0,4x-0,6=0,2(1-x) equation: 



0.6(x+2)-(0.4x-0.6=0.2(1-x)

We move all terms to the left:

0.6(x+2)-(0.4x-0.6-(0.2(1-x))=0

We add all the numbers together, and all the variables

0.6(x+2)-(0.4x-0.6-(0.2(-1x+1))=0

We multiply parentheses

0.6x-(0.4x-0.6-(0.2(-1x+1))+1.2=0

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