0,5(12-p)=p-(27-p)

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Solution for 0,5(12-p)=p-(27-p) equation: 



0.5(12-p)=p-(27-p)

We move all terms to the left:

0.5(12-p)-(p-(27-p))=0

We add all the numbers together, and all the variables

0.5(-1p+12)-(p-(-1p+27))=0

We multiply parentheses

-0.5p-(p-(-1p+27))+6=0



We calculate terms in parentheses: -(p-(-1p+27)), so:

p-(-1p+27)

We get rid of parentheses

p+1p-27

We add all the numbers together, and all the variables

2p-27

Back to the equation:

-(2p-27)



We get rid of parentheses

-0.5p-2p+27+6=0

We add all the numbers together, and all the variables

-2.5p+33=0

We move all terms containing p to the left, all other terms to the right

-2.5p=-33

p=-33/-2.5

p=13+0.5/2.5

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