0,3x(4x+5)=(1,2x+3)x

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Solution for 0,3x(4x+5)=(1,2x+3)x equation: 



0.3x(4x+5)=(1.2x+3)x

We move all terms to the left:

0.3x(4x+5)-((1.2x+3)x)=0

We multiply parentheses

0x^2+0x-((1.2x+3)x)=0



We calculate terms in parentheses: -((1.2x+3)x), so:

(1.2x+3)x

We multiply parentheses

x^2+3x

Back to the equation:

-(x^2+3x)



We add all the numbers together, and all the variables

x^2+x-(x^2+3x)=0

We get rid of parentheses

x^2-x^2+x-3x=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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