0,3(2x-1)=0,8+0,2(10x-2)

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Solution for 0,3(2x-1)=0,8+0,2(10x-2) equation: 



0.3(2x-1)=0.8+0.2(10x-2)

We move all terms to the left:

0.3(2x-1)-(0.8+0.2(10x-2))=0

We multiply parentheses

0.6x-(0.8+0.2(10x-2))-0.3=0



We calculate terms in parentheses: -(0.8+0.2(10x-2)), so:

0.8+0.2(10x-2)

determiningTheFunctionDomain
0.2(10x-2)+0.8

We multiply parentheses

2x-0.4+0.8

We add all the numbers together, and all the variables

2x+0.4

Back to the equation:

-(2x+0.4)



We get rid of parentheses

0.6x-2x-0.4-0.3=0

We add all the numbers together, and all the variables

-1.4x-0.7=0

We move all terms containing x to the left, all other terms to the right

-1.4x=0.7

x=0.7/-1.4

x=-0.7/1.4

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