0,25x2-x-3=0

Solution for 0,25x2-x-3=0 equation:

0.25x^2-x-3=0

We add all the numbers together, and all the variables

0.25x^2-1x-3=0

a = 0.25; b = -1; c = -3;
Δ = b2-4ac
Δ = -12-4·0.25·(-3)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-2}{2*0.25}=\frac{-1}{0.5}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+2}{2*0.25}=\frac{3}{0.5}
=6
$