0,01v2-0,0025v-110=0

Solution for 0,01v2-0,0025v-110=0 equation:

0.01v^2-0.0025v-110=0

a = 0.01; b = -0.0025; c = -110;
Δ = b2-4ac
Δ = -0.00252-4·0.01·(-110)
Δ = 4.40000625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.0025)-\sqrt{4.40000625}}{2*0.01}=\frac{0.0025-\sqrt{4.40000625}}{0.02}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.0025)+\sqrt{4.40000625}}{2*0.01}=\frac{0.0025+\sqrt{4.40000625}}{0.02}
$