0(x)=-1/3x-2

Solution for 0(x)=-1/3x-2 equation:

0(x)=-1/3x-2

We move all terms to the left:

0(x)-(-1/3x-2)=0


Domain of the equation: 3x-2)!=0

x∈R


We add all the numbers together, and all the variables

x-(-1/3x-2)=0

We get rid of parentheses

x+1/3x+2=0

We multiply all the terms by the denominator


x*3x+2*3x+1=0

Wy multiply elements

3x^2+6x+1=0

a = 3; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·3·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{6}}{2*3}=\frac{-6-2\sqrt{6}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{6}}{2*3}=\frac{-6+2\sqrt{6}}{6}
$