/x-5x+4=10

Solution for /x-5x+4=10 equation:

/x-5x+4=10

We move all terms to the left:

/x-5x+4-(10)=0


Domain of the equation: x!=0

x∈R


We add all the numbers together, and all the variables

-5x+/x-6=0

We multiply all the terms by the denominator


-5x*x-6*x+=0

We add all the numbers together, and all the variables

-6x-5x*x=0

Wy multiply elements

-5x^2-6x=0

a = -5; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-5)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-5}=\frac{0}{-10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-5}=\frac{12}{-10}
=-1+1/5
$