/x-4+7x=36

Solution for /x-4+7x=36 equation:

/x-4+7x=36

We move all terms to the left:

/x-4+7x-(36)=0


Domain of the equation: x!=0

x∈R


We add all the numbers together, and all the variables

7x+/x-40=0

We multiply all the terms by the denominator


7x*x-40*x+=0

We add all the numbers together, and all the variables

-40x+7x*x=0

Wy multiply elements

7x^2-40x=0

a = 7; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·7·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*7}=\frac{80}{14}
=5+5/7
$