/n+24=3n

Solution for /n+24=3n equation:

/n+24=3n

We move all terms to the left:

/n+24-(3n)=0


Domain of the equation: n!=0

n∈R


We add all the numbers together, and all the variables

-3n+/n+24=0

We multiply all the terms by the denominator


-3n*n+24*n+=0

We add all the numbers together, and all the variables

24n-3n*n=0

Wy multiply elements

-3n^2+24n=0

a = -3; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-3)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-3}=\frac{-48}{-6}
=+8
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-3}=\frac{0}{-6}
=0
$