/k2+9=30

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Solution for /k2+9=30 equation: 



/k2+9=30

We move all terms to the left:

/k2+9-(30)=0



Domain of the equation: k2!=0

k^2!=0/

k^2!=√0

k!=0

k∈R



We add all the numbers together, and all the variables

/k2-21=0

We multiply all the terms by the denominator


-21*k2+=0

We add all the numbers together, and all the variables

-21k^2=0

a = -21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-21)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{-42}=0$

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