/d+4=10+5d

Solution for /d+4=10+5d equation:

/d+4=10+5d

We move all terms to the left:

/d+4-(10+5d)=0


Domain of the equation: d!=0

d∈R


We add all the numbers together, and all the variables

/d-(5d+10)+4=0

We get rid of parentheses

/d-5d-10+4=0

We multiply all the terms by the denominator


-5d*d-10*d+4*d+=0

We add all the numbers together, and all the variables

-6d-5d*d=0

Wy multiply elements

-5d^2-6d=0

a = -5; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-5)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-5}=\frac{0}{-10}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-5}=\frac{12}{-10}
=-1+1/5
$