/I)3x+12=60

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Solution for /I)3x+12=60 equation: 



/)3I+12=60

We move all terms to the left:

/)3I+12-(60)=0



Domain of the equation: )3I+12-60!=0

We move all terms containing I to the left, all other terms to the right

)3I!=48

I!=48/1

I!=48

I∈R



We multiply all the terms by the denominator


=0

I=0/1

I=0

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