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/9x=x+8
We move all terms to the left:
/9x-(x+8)=0
Domain of the equation: 9x!=0We get rid of parentheses
x!=0/9
x!=0
x∈R
/9x-x-8=0
We multiply all the terms by the denominator
-x*9x-8*9x+=0
We add all the numbers together, and all the variables
-x*9x-8*9x=0
Wy multiply elements
-9x^2-72x=0
a = -9; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·(-9)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*-9}=\frac{0}{-18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*-9}=\frac{144}{-18} =-8 $
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