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/8x-5=5x+13*
We move all terms to the left:
/8x-5-(5x+13*)=0
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
/8x-(+5x)-5=0
We get rid of parentheses
/8x-5x-5=0
We multiply all the terms by the denominator
-5x*8x-5*8x+=0
We add all the numbers together, and all the variables
-5x*8x-5*8x=0
Wy multiply elements
-40x^2-40x=0
a = -40; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·(-40)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*-40}=\frac{0}{-80} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*-40}=\frac{80}{-80} =-1 $
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