/8x+6=-2x+2

Solution for /8x+6=-2x+2 equation:

/8x+6=-2x+2

We move all terms to the left:

/8x+6-(-2x+2)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We get rid of parentheses

/8x+2x-2+6=0

We multiply all the terms by the denominator


2x*8x-2*8x+6*8x+=0

We add all the numbers together, and all the variables

2x*8x-2*8x+6*8x=0

Wy multiply elements

16x^2-16x+48x=0

We add all the numbers together, and all the variables

16x^2+32x=0

a = 16; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·16·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*16}=\frac{-64}{32}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*16}=\frac{0}{32}
=0
$