/8v-4(v+8)=8

Solution for /8v-4(v+8)=8 equation:

/8v-4(v+8)=8

We move all terms to the left:

/8v-4(v+8)-(8)=0


Domain of the equation: 8v!=0

v!=0/8

v!=0

v∈R


We multiply parentheses

/8v-4v-32-8=0

We multiply all the terms by the denominator


-4v*8v-32*8v-8*8v+=0

We add all the numbers together, and all the variables

-4v*8v-32*8v-8*8v=0

Wy multiply elements

-32v^2-256v-64v=0

We add all the numbers together, and all the variables

-32v^2-320v=0

a = -32; b = -320; c = 0;
Δ = b2-4ac
Δ = -3202-4·(-32)·0
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{102400}=320$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-320}{2*-32}=\frac{0}{-64}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+320}{2*-32}=\frac{640}{-64}
=-10
$