/8h+16h-12=24h-12

Solution for /8h+16h-12=24h-12 equation:

/8h+16h-12=24h-12

We move all terms to the left:

/8h+16h-12-(24h-12)=0


Domain of the equation: 8h!=0

h!=0/8

h!=0

h∈R


We add all the numbers together, and all the variables

16h+/8h-(24h-12)-12=0

We get rid of parentheses

16h+/8h-24h+12-12=0

We multiply all the terms by the denominator


16h*8h-24h*8h+12*8h-12*8h+=0

We add all the numbers together, and all the variables

16h*8h-24h*8h+12*8h-12*8h=0

Wy multiply elements

128h^2-192h^2+96h-96h=0

We add all the numbers together, and all the variables

-64h^2=0

a = -64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-64)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{-128}=0$