/7y+20=11y+4

Solution for /7y+20=11y+4 equation:

/7y+20=11y+4

We move all terms to the left:

/7y+20-(11y+4)=0


Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R


We get rid of parentheses

/7y-11y-4+20=0

We multiply all the terms by the denominator


-11y*7y-4*7y+20*7y+=0

We add all the numbers together, and all the variables

-11y*7y-4*7y+20*7y=0

Wy multiply elements

-77y^2-28y+140y=0

We add all the numbers together, and all the variables

-77y^2+112y=0

a = -77; b = 112; c = 0;
Δ = b2-4ac
Δ = 1122-4·(-77)·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-112}{2*-77}=\frac{-224}{-154}
=1+5/11
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+112}{2*-77}=\frac{0}{-154}
=0
$