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/7x-3x=5x+2
We move all terms to the left:
/7x-3x-(5x+2)=0
Domain of the equation: 7x!=0We add all the numbers together, and all the variables
x!=0/7
x!=0
x∈R
-3x+/7x-(5x+2)=0
We get rid of parentheses
-3x+/7x-5x-2=0
We multiply all the terms by the denominator
-3x*7x-5x*7x-2*7x+=0
We add all the numbers together, and all the variables
-3x*7x-5x*7x-2*7x=0
Wy multiply elements
-21x^2-35x^2-14x=0
We add all the numbers together, and all the variables
-56x^2-14x=0
a = -56; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-56)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-56}=\frac{0}{-112} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-56}=\frac{28}{-112} =-1/4 $
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