/7x-16=1/6x+18

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Solution for /7x-16=1/6x+18 equation:



/7x-16=1/6x+18
We move all terms to the left:
/7x-16-(1/6x+18)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 6x+18)!=0
x∈R
We get rid of parentheses
/7x-1/6x-18-16=0
We calculate fractions
(*6x)/42x^2+(-7x)/42x^2-18-16=0
We add all the numbers together, and all the variables
(+*6x)/42x^2+(-7x)/42x^2-18-16=0
We add all the numbers together, and all the variables
(+*6x)/42x^2+(-7x)/42x^2-34=0
We multiply all the terms by the denominator
(+*6x)+(-7x)-34*42x^2=0
Wy multiply elements
-1428x^2+(+*6x)+(-7x)=0
We get rid of parentheses
-1428x^2+*6x-7x=0
We add all the numbers together, and all the variables
-1428x^2-7x+*6x=0

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