/7(x-4)-2x=19+3(x+3)

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Solution for /7(x-4)-2x=19+3(x+3) equation: 



/7(x-4)-2x=19+3(x+3)

We move all terms to the left:

/7(x-4)-2x-(19+3(x+3))=0



Domain of the equation: 7(x-4)!=0

x∈R



We add all the numbers together, and all the variables

-2x+/7(x-4)-(19+3(x+3))=0

We multiply all the terms by the denominator


-2x*7(x-4)-((19+3(x+3)))*7(x-4)+=0



We calculate terms in parentheses: -((19+3(x+3)))*7(x-4), so:

(19+3(x+3)))*7(x-4



We add all the numbers together, and all the variables

-2x*7(x-4)-((19+3(x+3)))*7(x-4)=0

Wy multiply elements

-14x^2(x-((19+3(x+3)))*7(x-4)=0

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