/7(2x+4)-5(x-10)=60

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Solution for /7(2x+4)-5(x-10)=60 equation: 



/7(2x+4)-5(x-10)=60

We move all terms to the left:

/7(2x+4)-5(x-10)-(60)=0



Domain of the equation: 7(2x+4)!=0

x∈R



We multiply parentheses

/7(2x+4)-5x+50-60=0

We multiply all the terms by the denominator


-5x*7(2x+4)+50*7(2x+4)-60*7(2x+4)+=0

We add all the numbers together, and all the variables

-5x*7(2x+4)+50*7(2x+4)-60*7(2x+4)=0

Wy multiply elements

-35x^2(2+350x(2-420x(2=0

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