/7(2q+1)=35

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Solution for /7(2q+1)=35 equation: 



/7(2q+1)=35

We move all terms to the left:

/7(2q+1)-(35)=0



Domain of the equation: 7(2q+1)!=0

q∈R



We multiply all the terms by the denominator


-35*7(2q+1)+=0

We add all the numbers together, and all the variables

-35*7(2q+1)=0

Wy multiply elements

-245q(2=0

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