/6x+12=2x+28,

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Solution for /6x+12=2x+28, equation:



/6x+12=2x+28.
We move all terms to the left:
/6x+12-(2x+28.)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
We add all the numbers together, and all the variables
/6x-(2x+28)+12=0
We get rid of parentheses
/6x-2x-28+12=0
We multiply all the terms by the denominator
-2x*6x-28*6x+12*6x+=0
We add all the numbers together, and all the variables
-2x*6x-28*6x+12*6x=0
Wy multiply elements
-12x^2-168x+72x=0
We add all the numbers together, and all the variables
-12x^2-96x=0
a = -12; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·(-12)·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*-12}=\frac{0}{-24} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*-12}=\frac{192}{-24} =-8 $

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