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/5x+8=11+2x
We move all terms to the left:
/5x+8-(11+2x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
/5x-(2x+11)+8=0
We get rid of parentheses
/5x-2x-11+8=0
We multiply all the terms by the denominator
-2x*5x-11*5x+8*5x+=0
We add all the numbers together, and all the variables
-2x*5x-11*5x+8*5x=0
Wy multiply elements
-10x^2-55x+40x=0
We add all the numbers together, and all the variables
-10x^2-15x=0
a = -10; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-10)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-10}=\frac{30}{-20} =-1+1/2 $
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