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/5m-8-3m=16
We move all terms to the left:
/5m-8-3m-(16)=0
Domain of the equation: 5m!=0We add all the numbers together, and all the variables
m!=0/5
m!=0
m∈R
-3m+/5m-24=0
We multiply all the terms by the denominator
-3m*5m-24*5m+=0
We add all the numbers together, and all the variables
-3m*5m-24*5m=0
Wy multiply elements
-15m^2-120m=0
a = -15; b = -120; c = 0;
Δ = b2-4ac
Δ = -1202-4·(-15)·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-120}{2*-15}=\frac{0}{-30} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+120}{2*-15}=\frac{240}{-30} =-8 $
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