/5+x2=2x2+13

Solution for /5+x2=2x2+13 equation:

/5+x2=2x^2+13

We move all terms to the left:

/5+x2-(2x^2+13)=0

We add all the numbers together, and all the variables

x^2-(2x^2+13)+/5=0

We get rid of parentheses

x^2-2x^2-13+/5=0

We multiply all the terms by the denominator


x^2*5-2x^2*5-13*5+=0

We add all the numbers together, and all the variables

x^2*5-2x^2*5=0

Wy multiply elements

5x^2-10x^2=0

We add all the numbers together, and all the variables

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$