/5(x-2)=1/10(x+6)

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Solution for /5(x-2)=1/10(x+6) equation: 



/5(x-2)=1/10(x+6)

We move all terms to the left:

/5(x-2)-(1/10(x+6))=0



Domain of the equation: 5(x-2)!=0

x∈R





Domain of the equation: 10(x+6))!=0

x∈R



We calculate fractions


(*10(x+6)))/(5(x-2)*10(x+6)))+(-5xx/(5(x-2)*10(x+6)))=0



We calculate terms in parentheses: +(*10(x+6)))/(5(x-2)*10(x+6)))+(-5xx/(5(x-2)*10(x+6))), so:

*10(x+6)))/(5(x-2)*10(x+6)))+(-5xx/(5(x-2)*10(x+6))

We add all the numbers together, and all the variables

*10(x+6)))/(5(x-2)*10(x+6)))+(-5xx/(5(x-2)*10(x

We multiply all the terms by the denominator


*10(x+6)))-2*10x*(5(x+6)))+(-5xx-2*10x*(5(x

Back to the equation:

+(*10(x+6)))-2*10x*(5(x+6)))+(-5xx-2*10x*(5(x)

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