/5(x+1)=2x-3-4(x+5)

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Solution for /5(x+1)=2x-3-4(x+5) equation:



/5(x+1)=2x-3-4(x+5)
We move all terms to the left:
/5(x+1)-(2x-3-4(x+5))=0
Domain of the equation: 5(x+1)!=0
x∈R
We multiply all the terms by the denominator
-((2x-3-4(x+5)))*5(x+1)+=0
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We add all the numbers together, and all the variables
-((2x-3-4(x+5)))*5(x+1)=0
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1
We calculate terms in parentheses: -((2x-3-4(x+5)))*5(x+1), so:
(2x-3-4(x+5)))*5(x+1

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