/4m-4-8=-2m+12

Solution for /4m-4-8=-2m+12 equation:

/4m-4-8=-2m+12

We move all terms to the left:

/4m-4-8-(-2m+12)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R


We add all the numbers together, and all the variables

/4m-(-2m+12)-12=0

We get rid of parentheses

/4m+2m-12-12=0

We multiply all the terms by the denominator


2m*4m-12*4m-12*4m+=0

We add all the numbers together, and all the variables

2m*4m-12*4m-12*4m=0

Wy multiply elements

8m^2-48m-48m=0

We add all the numbers together, and all the variables

8m^2-96m=0

a = 8; b = -96; c = 0;
Δ = b2-4ac
Δ = -962-4·8·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-96}{2*8}=\frac{0}{16}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+96}{2*8}=\frac{192}{16}
=12
$