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/3x-10x+6=1x
We move all terms to the left:
/3x-10x+6-(1x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-11x+/3x+6=0
We multiply all the terms by the denominator
-11x*3x+6*3x+=0
We add all the numbers together, and all the variables
-11x*3x+6*3x=0
Wy multiply elements
-33x^2+18x=0
a = -33; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-33)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-33}=\frac{-36}{-66} =6/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-33}=\frac{0}{-66} =0 $
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