/3(x+2)+4x-5=7(x+1)-6

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Solution for /3(x+2)+4x-5=7(x+1)-6 equation: 



/3(x+2)+4x-5=7(x+1)-6

We move all terms to the left:

/3(x+2)+4x-5-(7(x+1)-6)=0



Domain of the equation: 3(x+2)!=0

x∈R



We add all the numbers together, and all the variables

4x+/3(x+2)-(7(x+1)-6)-5=0

We multiply all the terms by the denominator


4x*3(x+2)-((7(x+1)-6))*3(x+2)-5*3(x+2)+=0



We calculate terms in parentheses: -((7(x+1)-6))*3(x+2), so:

(7(x+1)-6))*3(x+2



We add all the numbers together, and all the variables

4x*3(x+2)-((7(x+1)-6))*3(x+2)-5*3(x+2)=0

Wy multiply elements

12x^2(x-((7(x+1)-6))*3(x+2)-15x(x=0

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