/3(4+2b)-b=27

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Solution for /3(4+2b)-b=27 equation: 



/3(4+2b)-b=27

We move all terms to the left:

/3(4+2b)-b-(27)=0



Domain of the equation: 3(4+2b)!=0

b∈R



We add all the numbers together, and all the variables

/3(2b+4)-b-27=0

We add all the numbers together, and all the variables

-1b+/3(2b+4)-27=0

We multiply all the terms by the denominator


-1b*3(2b+4)-27*3(2b+4)+=0

We add all the numbers together, and all the variables

-1b*3(2b+4)-27*3(2b+4)=0

Wy multiply elements

-3b^2(2-81b(2=0

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