/3(23-2b)+3b=16

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Solution for /3(23-2b)+3b=16 equation: 



/3(23-2b)+3b=16

We move all terms to the left:

/3(23-2b)+3b-(16)=0



Domain of the equation: 3(23-2b)!=0

b∈R



We add all the numbers together, and all the variables

/3(-2b+23)+3b-16=0

We add all the numbers together, and all the variables

3b+/3(-2b+23)-16=0

We multiply all the terms by the denominator


3b*3(-2b+23)-16*3(-2b+23)+=0

We add all the numbers together, and all the variables

3b*3(-2b+23)-16*3(-2b+23)=0

Wy multiply elements

9b^2(--48b(-=0

We use the square of the difference formula

9b^2(+48b(-=0

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