/3(13x+12)=7x+6

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Solution for /3(13x+12)=7x+6 equation: 



/3(13x+12)=7x+6

We move all terms to the left:

/3(13x+12)-(7x+6)=0



Domain of the equation: 3(13x+12)!=0

x∈R



We get rid of parentheses

/3(13x+12)-7x-6=0

We multiply all the terms by the denominator


-7x*3(13x+12)-6*3(13x+12)+=0

We add all the numbers together, and all the variables

-7x*3(13x+12)-6*3(13x+12)=0

Wy multiply elements

-21x^2(1-18x(1=0

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